Question: A point light at position p is illuminating a point x on a surface. Explain why the strength of the light is proportional to

A point light at position p is illuminating a point x on a surface. Explain why the strength of the light is

A point light at position p is illuminating a point x on a surface. Explain why the strength of the light is proportional to 1/(p-x)2, i.e., inversely proportional to the squared distance between the light and the object. Does this rule is analogous with local light/illumination model? Explain.

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

The strength of the light at a point x on a surface is inversely proportional to the squared distanc... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Programming Questions!