A Poisson flow line has three stations with mean effective process times $(3,2,5).$ Assume a

closed system.

$($a$)(1$ pt$)$ Consider $=0$ and $=20.$ Compare the best CT and TH versus the CT and TH for

 

 the Poisson line. $[$Hint: the best CT and TH are obtained in a deterministic world.$]$ 

 

$($b$)(0\mathrm{.}5$ pts$)$ What is the minimum amount of WIP for the Poisson line that would result in a TH that 

 

is at least $95\%$ of the best TH$?$ What is the associated CT for this WIP level in the Poisson line?

 

 

$($c$)(0\mathrm{.}5$ pts$)$ Consider a reduction of $1$ in the bottlenecks mean effective process time. What are

the new CT and TH for $=0$ and $=20?$

 

 

$($d$)(0\mathrm{.}5$ pts$)$ Now consider a reduction of $0\mathrm{.}5$ in the mean effective process time at each non$-$

bottleneck station. The bottlenecks process time remains at its original level. What are the

new CT and TH for $=0$ and $=20?$

 

 

$($e$)(0\mathrm{.}5$ pts$)$ If there is an improvement from the actions in

$($$\mathrm{f)},$ explain why it is surprising given the 

 

behavior of deterministic lines and why it is important.