Question: A positive integer n satisfies the equation (n + 1)! + (n+2)! = 440-n!. Waht is the sum of the digits of n?

A positive integer n satisfies the equation (n + 1)! + (n+2)!

A positive integer n satisfies the equation (n + 1)! + (n+2)! = 440-n!. Waht is the sum of the digits of n?

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