A pot of boiling soup with an internal temperature of 100 Fahrenheit was removed from the stove
Fantastic news! We've Found the answer you've been seeking!
Question:
A pot of boiling soup with an internal temperature of 100∘ Fahrenheit was removed from the stove to cool in a room at 77∘ F. After 18 minutes, the internal temperature of the soup was 95°F. Use Newton's law of cooling to write a formula that represents this situation. Round to four decimal places. T(t)= (Let t be the time measured in minutes.)
To the nearest minute, how long will it take the soup to cool to 87∘ F?
To the nearest degree, what will the temperature be after 1.3 hours?
Related Book For
Posted Date: