A programmer is asked to translate the following HLL code into MIPS Assembly language

int isa()= {10,20,30,-5,-15,40,50,-88,19,-33};

string hud="***";

for (int k=0;k<10;k++)

isa(k)=4*isa(k);

for (int k=0;k<10;k++)

cout << isa(k) << hud ; // print value

return 0;

The programmer asked you to help him complete the missing 10 statements in the MIPS code. In your answers, please separate the opcode and the operands by ONE space only as follows: sub $t9,$t8,$t5

.data

isa: .word 10,20,30,-5,-15,40,50,-88,19,-33

hud: .asciiz "***"

.text

.globl bonus

bonus:

Blank 1

li $t1,10

next: Blank 2

Blank 3

Blank 4

addi $t0,$t0,4

addi $t1,$t1,-1

Blank 5

la $t0,isa

Blank 6

Go: lw $a0,0($t0)

Blank 7

syscall

la $a0,hud

li $v0,4

syscall

Blank 8

Blank 9

Blank 10

li $v0,10 # exit program

syscall