A project has these cash flows: $$2,0003$ years ago, $$1,000$ now and $-$$$2,000$ three years from now. Which is the correct formula for computing today's value of

these cash flows given a $6\%$ rate of interest?

Today's value $=$$$2,000(1+0\mathrm{.}06{)}^3+$$$1,000(1+0\mathrm{.}06{)}^0-$$$2,\frac{000}{(1+0\mathrm{.}06{)}^3}$

Today's value $=$$$2,000+$$$1,000-$$$2,000$

Today's value $=-$$$2,000(1+0\mathrm{.}06{)}^3-$$$1,000(1+0\mathrm{.}06{)}^0+$$$2,\frac{000}{(1+0\mathrm{.}06{)}^3}$

Today's value $=$$$2,\frac{000}{(1+0\mathrm{.}06{)}^3}+$$$1,000(1+0\mathrm{.}06{)}^0-$$$2,000(1+0\mathrm{.}06{)}^3$