A proton (charge +e = 1.602 x 10-19 C) moves in a straight line from point a to point b inside a linear accelerator, with a total distance d = 0.50 m. The electric field is uniform along this line, with magnitude E = 1.5 x 107 V/m = 1.5 x 107 N/C in the direction from a to b. Determine a) the force on the proton; b) the work done on it by the field; c) the potential difference Va - Vb.

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Solution Given 19 Charge of proton e 1602 10 k Xs Distance d 050m 1 Electric field E 15 107 ... View the full answer