Question: A proton moving at speed v = 1 . 0 5 1 0 6 m / sv = 1 . 0 5 1 0 6

A proton moving at speed v=1.05106m/sv=1.05106m/s enters a region in space where a magnetic field given by B=(0.521T)zB=-0.521Tz^exists. The velocity vector of the proton is at an angle =56.9 with respect to the positive z-axis.(You may enter your calculation using scientific notation.)
(a) Calculate the radius, r, of the trajectory projected onto a plane perpendicular to the magnetic field (in the xy-plane).
1.00E-2 Numeric Response 1.Edit Unavailable. 1.00E-2 incorrect.m
(b) Calculate the period, T, of the motion in that plane.
1.26E-7 Numeric Response 2.Edit Unavailable. 1.26E-7 correct.s
(c) Calculate the frequency, f, of the motion in that plane.
7.94E6 Numeric Response 3.Edit Unavailable. 7.94E6 correct.Hz
(d) Calculate the pitch of the motion (the distance traveled by the proton in the direction of the magnetic field in 1 period).
1.10E-1 Numeric Response 4.Edit Unavailable. 1.10E-1 incorrect.m

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