Question: A proton with a charge ( + e ) is moving with a velocity ( v ) at ( 4

A proton with a charge \(+e \) is moving with a velocity \( v \) at \(40^{\circ}\) to the direction of a magnetic field \( B \). The component of the resulting force on the proton in the direction perpendicular to \( v \) is
A proton with a charge \ ( + e \ ) is moving with

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