Question: ) A quality analyst wants to construct a sample mean chart (x-bar) for controlling a packaging process. Each day last week, he randomly selected four
) A quality analyst wants to construct a sample mean chart (x-bar) for controlling a packaging process. Each day last week, he randomly selected four packages and weighed each. The data from that activity appears below.
| Weight | ||||
| Day | Package 1 | Package 2 | Package 3 | Package 4 |
| Monday | 23 | 22 | 23 | 24 |
| Tuesday | 23 | 21 | 19 | 21 |
| Wednesday | 20 | 19 | 20 | 21 |
| Thursday | 18 | 19 | 20 | 19 |
| Friday | 18 | 20 | 22 | 20 |
Calculate upper and lower control limits that allow for natural variations.
A- 18.9, 22.3
B-19.0, 22.2
C-18.6, 22.6
D-19.3, 22.0
Answer: C
The five sample means are 23, 21, 20, 19, and 20. The mean of all sample means is 20.6
UCL = 20.6 + .729*2.8 LCL = 20.6 - .729*2.8 =
How they got the .729 and 2.8 values?
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