Question: A quality analyst wants to construct a sample mean chart for controlling a packaging process. Each day last week, he randomly selected four packages and
A quality analyst wants to construct a sample mean chart for controlling a packaging process. Each day last week, he randomly selected four packages and weighed each. The data from that activity appears below.
|
| Weight | |||
| Day | Package 1 | Package 2 | Package 3 | Package 4 |
| Monday | 23 | 22 | 23 | 24 |
| Tuesday | 23 | 21 | 19 | 21 |
| Wednesday | 20 | 19 | 20 | 21 |
| Thursday | 18 | 19 | 20 | 19 |
| Friday | 18 | 20 | 22 | 20 |
The mean of all sample means is:
| a. | 20 | |
| b. | 23 | |
| c. | 20.6 | |
| d. | 19 | |
| e. | 21 |
Calculate 3 upper and lower control limits for the Mean.
| a. UCL = 23.05; LCL = 18.15 | ||
| b. UCL = 26.6; LCL = 14.6 | ||
| c. UCL = 22.64; LCL = 18.56 | ||
| d. UCL = 22.21; LCL = 18.98 | ||
| e. UCL = 23.7; LCL = 17.5 |
Is this process in control?
| a. Monday sample is above the UCL; all others are within limits. The process is not in control. | ||
| b. Tuesday sample is above the UCL; all others are within limits. The process is not in control. | ||
| c. Wednesday sample is below the LCL; all others are within limits. The process is not in control. | ||
| d. Thursday sample is below the LCL; all others are within limits. The process is not in control. | ||
| e. All samples are within limits. The process is in control. |
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