Question: A random number generation device is expected to generate random values according to the Binomial distribution with n=5 and p=0.57. To ensure that the

A random number generation device is expected to generate random values according to the Binomial distribution with n=5 and p=0.57. To ensure that the device's random number generation is appropriate, its 1550 recent random numbers generated have been organized in the following table. If the Chi-squared goodness-of-fit test is used with a significance of 0.05 to test whether random values have been appropriately generated by the device, what is the P-value of the test rounded to two places after the decimal, and the decision made? 012345 Observed Frequency 13 165 429 528 323 92 P-value = 0.08 Decision: the Binomial distribution is a good fit. P-value = 0.12 Decision: the Binomial distribution is not a good fit. Decision: the Binomial distribution is not a good fit. Decision: the Binomial distribution is not a good fit. P-value = 0.05/ P-value = 0.08 P-value = 0.05/ P-value = 0.12 / Decision: the Binomial distribution is a good fit. Decision: the Binomial distribution is a good fit. O O O O O

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