Question: A random number generation device is expected to generate random values according to the Binomial distribution with n=5 and p=0.37. To ensure that the

A random number generation device is expected to generate random values according

A random number generation device is expected to generate random values according to the Binomial distribution with n=5 and p=0.37. To ensure that the device's random number generation is appropriate, its 1500 recent random numbers generated have been organized in the following table. If the Chi-squared goodness-of-fit test is used with a significance of 0.05 to test whether random values have been appropriately generated by the device, what is the P-value of the test rounded to two places after the decimal, and the decision made? Observed Frequency 0 145 1 414 1 2 3 4 5 498 346 92 5 00 P-value = 0.02 / Decision: the Binomial distribution is a good fit. P-value = 0.08 / Decision: the Binomial distribution is a good fit. P-value = 0.08 Decision: the Binomial distribution is not a good fit. P-value = 0.02 / Decision: the Binomial distribution is not a good fit. P-value = 0.05/ Decision: the Binomial distribution is a good fit. P-value = 0.05/ Decision: the Binomial distribution is not a good fit. O O

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