A reaction mixture $2Mg(s)+O_2((g))2$MgO$(s)$ contains $38\mathrm{.}6gMg$ and $53\mathrm{.}2g{O}_2.$ The reaction yielded $56\mathrm{.}4g$ of product. What is the percent yield of MgO $?$

$63\mathrm{.}0\%$

$84\mathrm{.}3\%$

$88\mathrm{.}0\%$