A recent personalized information sheet from your wireless phone carrier claims that the mean duration of all your phone calls was u = 3.9 minutes with a standard deviation of o = 2.8 minutes. From a random sample of n = 45 calls, your parents computed a sample mean of x = 4.4 minutes and a sample standard deviation of s = 3.3 minutes. Complete parts a through e below. O A. O B. &C. OD. The mean is 3.9 and the standard deviation is 2.8 (Round to two decimal places as needed.) b. What are the mean and standard deviation of the data distribution? The mean is 4.4 and the standard deviation is 3.3 (Round to two decimal places as needed.) C. Find the mean and standard deviation of the sampling distribution of the sample mean. The mean is 3.90 and the standard deviation is 42 . (Round to two decimal places as needed.) d. Is the sample mean of 4.4 minutes unusually high? Find its z-score and comment. Since z= 1.19 , the sample mean is not unusually high. (Round to two decimal places as needed.) e. Your parents told you that they will kick you off the plan when they find a sample mean larger than 4.3 minutes. How likely is this to happen? P(x> 4.3 minutes) = (Round to three decimal places as needed. )