Question: A rectangular box has height z , the length of the two edges of its base are x and y . Then, the volume of

A rectangular box has height

z

, the length of the two edges of its base are

x

and

y

.\ Then, the volume of this box is a function of

x,y,z

: Volume

=V(x,y,z)=

(input a function, write in increasing alphabetic order of

x,y,z

. omit the product sign * as before)\ Evaluate this volume function:

V(2,3,5)=

V(1,4,7)=

\ The surface area of this box is also function of

x,y,z

: Surface area

=A(x,y,z)=

(Input a sum of three terms, write in the order of increasing alphabetic order, both for the individual term, and for all the terms in the sum. And use same other input rules as before. E.g., input

xz5+z3y+y20x

as

20xy+5xz+3yz

, this is because

A(2,3,5)=A(1,4,7)=V(x,y,z)A(x,y,z)R^(3)V(x,y,z)A(x,y,z)R^(3)V(x,y,z)A(x,y,z)(0,\\\\infty )xy x, and xy
 A rectangular box has height z, the length of the two

A rectangular box has height z, the length of the two edges of its base are x and y. Then, the volume of this box is a function of x,y,z : Volume =V(x,y,z)= (input a function, write in increasing alphabetic order of x,y,z. omit the product sign * as before) Evaluate this volume function: V(2,3,5)= V(1,4,7)= The surface area of this box is also function of x,y,z : Surface area =A(x,y,z)= (Input a sum of three terms, write in the order of increasing alphabetic order, both for the individual term, and for all the terms in the sum. And use same other input rules as before. E.g., input xz5+z3y+y20x as 20xy+5xz+3yz, this is because x

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