A rectangular member is loaded by the axial force as shown.

For $P=3\mathrm{.}5kN,$ and $=40,$

determine the resultant normal force N on the inclined surface.

$2\mathrm{.}68$

$\frac{100}{1}$ point

For $=32,$ if the resulting normal force on the incline surface is

$N=16\mathrm{.}0kN,$