Question: ( a ) Register modified: $t 0 ( b ) Updated value: $t 0 = $s 1 < < 2 = 0 x 1 <

(a) Register modified: $t0
(b) Updated value: $t0= $s1<<2=0x1<<2=0x4
(c) Next instruction: Line2
(a) Register modified: $t0
(b) Updated value: $t0= $t0+ $s0=0x4+0x4000=0x4004
(c) Next instruction: Line3
(a) Register modified: $t1
(b) Updated value: $t1= Value at memory address 0x4006(little-endian)=0x4168(sign-extended to 0xFFFF4168)
(c) Next instruction: Line4
(a) Register modified: $t2
(b) Updated value: $t2=($t1<0)=(0xFFFF4168<0)=0
(c) Next instruction: Line5
(a) No change in registers and memory
(b) Next instruction: Line6
(a) No change in registers and memory
(b) Next instruction: Line7
(a) Register modified: $t1
(b) Updated value: $t1= $t1-1=0xFFFF4167
(c) Next instruction: Line8
(a) No change in registers and memory
(b) Next instruction: Line10
(a) Register modified: $t1
(b) Updated value: $t1= $t1+1=0xFFFF4168
(c) Next instruction: None (Direct jump to Line10)
(a) Memory modified: Address 0x4006=0x41
(b) Next instruction: None (End of program)
Explanation:
Line 1: $s1(0x1) is left-shifted by 2 bits, resulting in $t0=0x4.
Line 2: $t0(0x4) is added to $s0(0x4000), resulting in $t0=0x4004.
Line 3: Loads the half-word from memory address 0x4004+2=0x4006(little-endian) into $t1. The value at 0x4006 is 0x4168.
Line 4: Compares $t1(0xFFFF4168) with 0. Since $t1 is not less than 0, $t2 is set to 0.
Line 5: Since $t2 is equal to 0, the branch is taken to Line9.
Line 6: Not executed because the branch condition is not satisfied.
Line 7: Not executed because the branch condition is not satisfied.
Line 8: Unconditional jump to Line10.
Line 9: Increases the value of $t1 by 1, making it 0xFFFF4168.
Line 10: Stores the byte value of $t1(0xFFFF4168) at memory address 0x4004+2=0x4006, replacing 0x68 with 0x68.

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