A roller coaster $(375$ kg$)$ moves from A $(5\mathrm{.}00$ m above the ground$)$ to B $(20\mathrm{.}0$ m above the ground$).$ Two non$-$conservative forces are present: friction does $2\mathrm{.}00\backslash$times $104$ J of work on the car, and a chain mechanism does $+3\mathrm{.}00\backslash$times $104$ J of work to help the car up a long climb. What is the change in the cars kinetic energy, KE $=$ KEf KEo, from A to B$?$