A rotating space station is said to create \"artificial gravity\"a loosely-dened term used for an acceleration that would be crudely similar to gravity. The outer wall of the rotating space station would become a floor for the astronauts, and centripetal acceleration supplied by the oor would allow astronauts to exercise and maintain muscle and bone strength more naturain than in non-rotating space environments. It the space station is 150 m in diameter, what angular velocity would produce an "artificial gravity" of 9.30 rnfs2 at the rim? 0.363 x Consider the dependence of centripetal acceleration on tangential speed and radius of the circular path. rpm Page 1 Extremely Sonny, A After verification I found out the mistake. The connected answer is : Radius of the spacestation = 150 m = 75 m 2 = R Let w= Angular velocity The centripetal acceleration supplied by the floor = V 2 R ( v = Tangential speed) we know, V = WOR N 2 Wo- R 2 = 10 2 R R Centripetal acceleration of 9. 80 m /s2 is so to be produced. = 980 = > co2 (75 ) = 9.80 co = 0. 362 mad / s 0. 362 road 0 . 362 X 60 rad Is 60 S = 21. 72 road /8min [ : 1 min . = 60s 2TT radians is 1 sonotation. ". W = 21. 72 rotations pen min. 2 IT = 3. 45 7 rpm where rpm is rotations pen min