Question: 3. If the mean income for people in the US were $45,000 with a variance of 625000000, what would be the probability that a randomly
3. If the mean income for people in the US were $45,000 with a variance of 625000000, what would be the probability that a randomly chosen American will have an income greater than $95,000?
4. Bob takes a survey and is told that his z-score is 1.5. Bob was like, “So what??? Does this mean that I’m weird?” What do you tell Bob? Bob is a little above average.
5. It is predicted that 13.2% of women born today will be diagnosed with breast cancer. What is a z-score for this percentage?
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Probability E 3 and So 2500 above 45000 2320 ... View full answer
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