A serial process has $4$ steps $-$ A $(4),$ B$(6),$ C$(2),$ D$(4)-$ that have to be performed in this order. The numbers in parentheses are the times $($in minutes$)$ needed to process a unit. The bottleneck step here is D B A CA serial process has $4$ steps $-$ A$(4),$ B$(6),$ C$(2),$ D$(5)-$ that have to be performed in this order. The numbers in parentheses are the times $($in minutes$)$ needed to process a unit. The capacity of this process $($in units per hour$)$ is: $10301512$A serial process has $4$ steps $-$ A$(4),$ B$(6),$ C$(2),$ D$(5)-$ that have to be performed in this order. The numbers in parentheses are the times $($in minutes$)$ needed to process a unit. When this process is running, we can expect it to produce one finished unit every: $4$ minutes $6$ minutes $17$ minutes $2$ minutesA serial process has $4$ steps $-$ A$(4),$ B$(3),$ Q$(6),$ D$(2)-$ that have to be performed in this order. The numbers in parentheses are the times $($in minutes$)$ needed to process a unit. The utilization of this process is $33\%50\%62\mathrm{.}5$ x $67\%$A serial process has $4$ steps $-$ A$(4),$ B$(3).$ C$(6),$ D$(2)-$ that have to be performed in this order. The numbers in parentheses are the times $($in minutes$)$ needed to process a unit. The total idle time per unit produced is: $3$ minutes $9$ minutes $2$ minutes $4$ minutes