A simple pendulum, $2\mathrm{.}6$ m in length, is released with a push when the support string is at an angle of $45\mathrm{.}0$ from the vertical. If the initial speed of the suspended mass is $1\mathrm{.}25\frac{m}{s}$ when at the release point, what is its speed at the bottom of the swing? $(g=9\mathrm{.}8\frac{m}{s^2})$

$4\mathrm{.}1\frac{m}{s}$

$3\mathrm{.}9\frac{m}{s}$

$4\mathrm{.}1\frac{m}{s}$

$16\frac{m}{s}$

$7\mathrm{.}2\frac{m}{s}$