A simple pendulum suspended in a rocket ship has a period $T_0.$ Assume that the rocket ship is near the earth in a uniform gravitational field.

If the ship accelerates downward at $9\mathrm{.}81\frac{m}{s^2},$ the pendulum will no longer oscillate.

If the length of the pendulum is doubled, the new period will be: square root of $2$ times $T_0.$

$q,$

If the ship accelerates upward, the period increases.

$q,$

If the ship moves upward with a constant velocity, the period increases.

$$

If the mass of the pendulum is halved, the period decreases.

Tries $0/12$

A simple pendulum suspended in a rocket ship has a period $T_0.$ Assume that the rocket ship is near the earth in a uniform gravitational field.

If the ship accelerates downward at $9\mathrm{.}81\frac{m}{s^2},$ the pendulum will no longer oscillate.

If the length of the pendulum is doubled, the new period will be: square root of $2$ times $T_0.$

$q,$

If the ship accelerates upward, the period increases.

$q,$

If the ship moves upward with a constant velocity, the period increases.

$$

If the mass of the pendulum is halved, the period decreases.

Tries $0/12$