A skater is spinning at $5$ rev$/$s with her arms extended outward. In this position her moment of inertia with respoect to the vertical axis about which she is spinning is $50\mathrm{.}0$ kg m$2.$ She pulls her arms in close to her body changing her moment of inertia to $20\mathrm{.}0$ kg m$2.$ What is her new angular velocity?

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To find the skaters new angular velocity after pulling her arms in we can use the principle ... View the full answer