Question: A small block with mass 0 . 0 4 0 0 kgkg is moving in the xyxy - plane. The net force on the block

A small block with mass 0.0400 kgkg is moving in the xyxy-plane. The net force on the block is described by the potential-energy function U(x,y)=(5.75J/m2)x2(3.65J/m3)y3U(x,y)=(5.75J/m2)x2(3.65J/m3)y3.
Part A
What is the magnitude of the acceleration of the block when it is at the point xx =0.32 mm, yy =0.53 mm?
Express your answer with the appropriate units.
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Part B
What is the direction of the acceleration of the block when it is at the point xx =0.32 mm, yy =0.53 mm?
Express your answer in degrees.

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