Question: A solid body with a triangular cross - section floats in a fluid as shown below. The cross - section of the 2 ( d

A solid body with a triangular cross-section floats in a fluid as shown below. The cross-section of the 2(d): Noting that the submerged volume can be written as the difference between the total
volume of the floating object and the volume of the floating body above the free surface,
determine the value of hI in the figure above in metres. Hint: you might find the concept of
similar triangles usefiul here
Note: If you are unable to complete this part of the question, you can assume hl=2.0 and
proceed with the remainder of the question.
2(e): Determine the submerged depth (h2) of the floating object in metres:
2(f): Determine the width of the triangle (cl) at the waterline cross-section (in metres): 2(g): Noting that the distance (hcentroid) from the base of the floating object to the centroid of
the submerged volume can be written as:
hcentroid=h2[c3+2c13][c+c1]
Determine the distance (GB) between the centre of gravity (G) and the centre of buoyancy
(B) of the floating bodv (in metres):
Al2
2(h): Determine the second moment of area about the waterline cross-section of the body (in
m4). Note: Adopt the combination of L and cl; that generates the smallest second moment
of area. This is because the smallest second moment of area is critical in terms of stability.
2(i): Determine the distance (BM) between the centre of buoyancy (B) and metacentre (M) in
metres:
2(j): Determine the metacentric height (GM) for the floating body in metres.
2(k): State the value of the metacentric height necessary for neutral stability (in metres): 2(c): Determine the submerged volume of the body (in m3):
Answer: ,0.0135
2(d): Determine the value of hl in the figure above in metres.
Answer: 2.522
Note: If you are unable to complete this part of the question, you can assume hl=2.0 and
proceed with the remainder of the question.
2(e): Determine the submerged depth (h2) of the floating object in metres:
2(f): Determine the width of the triangle (cr) at the waterline cross-section (in metres):
2(g): Determine the distance (GB) between the centre of gravity (G) and the centre of buoyancy
(B) of the floating hodv (in metres):
2(h): Determine the second moment of area about the waterline cross-section of the body (in
m4). Note: Adopt the combination of L and c1; that generates the smallest second moment
of area. This is because the smallest second moment of area is critical in terms of stability.
2(i): Determine the distance (BM) between the centre of buoyancy (B) and metacentre (M) in
metres:
2(j): Determine the metacentric height (GM) for the floating body in metres.
Answer: ,-0.5000
body is unchanged over its length (L)=8 metres into the page. The height of the body (h)=3.4 metres
and its maximum width (c)=2.2 metres. The uniform density of the solid body (s)=450kgm3 and
the density of the fluid (f)=1000kgm3. Conduct an analysis of the stability of the floating body by
carrying out the following tasks: Answers are provided, just confused on the working and the steps to take for each question. Please solve the quesstions to arrive at the given answers :)
A solid body with a triangular cross - section

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Civil Engineering Questions!