Question: A solution is made by mixing 1 5 0 g of acetyl bromide ( C H 3 COBr ) and 9 0 . 5 g

A solution is made by mixing 150g of acetyl bromide (CH3COBr) and 90.5g of chloroform (CHCl3).
a.Compute for the mole fraction of acetyl bromide.
ANSWER: The mole fraction of acetyl bromide in the solution is Blank 5.
b.Compute the ppb of chloroform.
ANSWER: The concentration of chloroform is Blank 6108ppb.
A solution is made by mixing 150g of acetyl bromide (CH3COBr)

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