Question: (a) Solve for the forecast equation that minimizes the sum of squared error. x1=1 if day shift, 0 otherwise; x2=1 if evening shift, 0 otherwise.



(a) Solve for the forecast equation that minimizes the sum of squared error. x1=1 if day shift, 0 otherwise; x2=1 if evening shift, 0 otherwise. Yi= (b) Forecast the demand for glazed donuts (in dorens) for the day, avening, and night shifts of June 8 . June8dayshiftforecastJune8eveningshiftforecastJune8nightshiftforecantdozendozendozen \begin{tabular}{|c|c|c|} \hline Date & Shift & Demand (dozens) \\ \hline June 3 & Day & 58 \\ \hline & Evening & 46 \\ \hline & Night & 41 \\ \hline June 4 & Day & 65 \\ \hline & Evening & 42 \\ \hline June 5 & Day & 38 \\ \hline & Evening & 61 \\ \hline June 6 & Day & 47 \\ \hline & Night & 43 \\ \hline Evening & 59 \\ \hline \end{tabular} a) Solve for the forecast equation that minimizes the sum of squared error. x1=1 if day shift, 0 otherwise; x2=1 if evening shift, 0 otherwise. Y^t= (b) Forecast the demand for glazed donuts (in dozens) for the day, evening, and night shifts of June 8. June 8 day shift forecast dozen June 8 evening shift forecast dozen June 8 night shift forecast dozen \begin{tabular}{|c|c|c|} \hline Date & Shifn & Demand (dorent) \\ \hline luate-3 & Day & \\ \hline & Cweiso & 15 \\ \hline \end{tabular}
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