Question: A spring is stretched 1 9 0 mmmm by a 1 5 kgkg block. Part A If the block is displaced 8 0 mmmm downward

A spring is stretched 190 mmmm by a 15 kgkg block.
Part A
If the block is displaced 80 mmmm downward from its equilibrium position and given a downward velocity of 0.70 m/sm/s , determine the equation which describes the motion. Assume that positive displacement is downward.
y=9.74102sin7.19t0.190cos7.19ty=9.74102sin7.19t0.190cos7.19t y=9.74102cos7.19t8.00102sin7.19ty=9.74102cos7.19t8.00102sin7.19t y=9.74102sin7.19t+8.00102cos7.19ty=9.74102sin7.19t+8.00102cos7.19t y=9.74102sin7.19t+8.00102cos7.19ty=9.74102sin7.19t+8.00102cos7.19t
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Part B
What is the phase angle?
Express your answer with the appropriate units.
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