Question: A square loop of sidelength a and current I is suspended beneath a long straight wire of current Iw . Givens: a = 1 0

A square loop of sidelength a and current I is suspended beneath a long straight wire of current Iw. Givens: a=10cm, d=1cm, I=15A, M=76g, g=98ms2(a) Draw the B- eld created by the straight wire and write an expression for the B- eld a distance y from the wire. (your answer will be a function of y)(b) Draw the direction of the magnetic forces on each segment of the loop. (c) The loop has a total mass M. What current Iw is required to suspend the loop in the air against gravity. c.1) Write an expression for the force on segment 1. c.2) Write an integral expression for the force on segment 2.(Do not evaluate the integral) c.3) Write an expression for the force on segment 3. c.4) Write an integral expression for the force on segment 4.(Do not evaluate the integral) c.5) Write an expression for the force of gravity on the loop. c.6) Sum the forces and solve for Iw.(Iw will be huge

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