Question: A stop and wait data link protocol has a frame overhead (for headers and checksums) of H bits. The data frames contain L bits of

A stop and wait data link protocol has a frame overhead (for headers and checksums) of H bits. The data frames contain L bits of data, and have a total length of L+H bits; acknowledgement frames (RR) contain no data, and have a total length of H bits.

The bit rate of the link is D Mbps and the link latency is T S.

Given that H= 48 bits and L= 2091 bits, D=52 Mbps and T=5 S:

What is the minimum round trip time (in S) to send the data packet and receive the acknowledgement (RR)?

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