Question: A teller at a drive - up window at a bank had the following service times ( in minutes ) for 2 0 randomly selected

A teller at a drive-up window at a bank had the following service times (in minutes) for 20 randomly selected customers.
SAMPLE
1234
4.54.64.54.7
4.24.54.64.6
4.24.44.44.8
4.34.74.44.5
4.34.34.64.9
a) Determine the mean of each sample (2ms).
Mean sample 1: (4.5+4.2+4.2+4.3+4.3)/5=4.3
Mean sample 2: (4.6+4.5+4.4+4.7+4.3)/5=4.5
Mean sample 3: (4.5+4.6+4.4+4.4+4.6)/5=4.5
Mean sample 4: (4.7+4.6+4.8+4.5+4.9)/5=4.7
b) Suppose the process mean is unknown, estimate it (1m).
Mean process: (4.3+4.5+4.5+4.7)/4=4.5
c) Suppose the process standard deviation is 0.192, estimate the mean and standard deviation of the sampling distribution (4ms).
d) What would be the three-sigma control limits for the process, based on the information in part c)?(2ms) Using these control limits, what will be the percentage that the service times are not acceptable? (3ms)
e) What percentage that the service times are not acceptable would control limits of 4.14 and 4.86 provide? (3ms)
f) Calculate the limits of control charts for means and ranges using the Control Chat Factor Table. Are any samples beyond the control limits? If so, which ones? (4ms)
g) Why the control limits are different for means in parts d) and f)?(4ms)
h) If the process has a known mean of 4.4 and a known standard deviation of 0.18, what would be the three-sigma control limits for a mean chart? Are any sample means beyond the control limits? If so, which one(s)?(4ms)

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