A$.$ The image formed by the objective lens is $---$Select$---$real$$virtual and $---$Select$---$upright$$inverted $.$

B$.$ We use the image formed by the objective lens as the object for the eyepiece lens. The eyepiece lens then forms its own image. This image formed by the eyepiece lens is a $---$Select$---$real$$virtual image. For the eyepiece lens to form this kind of image, what must be true about the location of the image formed by the objective lens?

Score: $1$ out of $1$

Comment:

C$.$ The distance between the lenses is L $=15$ cm$,$ and the focal lengths are fobj $=1$ cm and feye $=8$ cm$.$ The object to be viewed, a cell, is placed a distance of $1\mathrm{.}154$ cm in front of the objective lens. What is the image distance of the objective lens image?

iobj $=$ cm

D$.$ How far is the objective lens image from the eyepiece lens?

oeye $=$ cm

E$.$ What is the magnitude of the distance between the eyepiece lens and the image that it forms?

$|$ieye$|=$ cm

Is the image formed by the eyepiece lens to the left or the right of the eyepiece lens? $---$Select$---$left$$right

F$.$ What is the magnification due to each individual lens?

mobj $=$

meye $=$

G$.$ The total magnification is the product of the magnification due to each individual lens, and it is the ratio of the final image height over the original object height. If you are viewing a cell with a size of $10$m$,$ what is the size $($absolute value$)$ of the image that you view by looking through the eyepiece?

size $=$m