A traffic flow relationship is given as q$=$kv$.$ Mean speed on a road in mi$/$h is given as:

v$=55$mihr$(0\mathrm{.}4$mi$2$veh$$hr$)$k

$$

where,

q$-$traffic flow $($veh$/$h$)$

v$-$speed $($mph$)$

k$-$ density $($veh$/$mi$)$

If the mean speed on the road during the peak hour is $40$mph$,$ calculate the maximum capacity of overall traffic volume for this road.