Question: A tuning fork vibrating at 312Hz falls from rest and accelerates at 9.8m/s2 . a) How far below the point of release is the tuning
A tuning fork vibrating at 312Hz falls from rest and accelerates at 9.8m/s2 . a) How far below the point of release is the tuning fork when waves of 485Hz reach the release point. Take speed of sound in air to be 340m/s.
Step by Step Solution
★★★★★
3.46 Rating (159 Votes )
There are 3 Steps involved in it
1 Expert Approved Answer
Step: 1 Unlock
f312 f485 a 98 v 340 vs 31248534... View full answer
Question Has Been Solved by an Expert!
Get step-by-step solutions from verified subject matter experts
Step: 2 Unlock
Step: 3 Unlock
