Question: ( * ) A Turing machine M ! { decides } a @lang L if > > [ 1 ] M ACCEPTS * { every

(*) A Turing machine M !{decides} a @lang L if
>>[1] M ACCEPTS *{every} string w\inL, and
>>[2] M REJECTS *{every} string w\in~L.
//
[nb] Recall that ~L=\S*-L.
//
(1) Create a single tape Turing machine M_1 to decides the @lang of binary strings that contain at least 2 consecutive *{1}s !{and} an even number of \[1]s.
\;
(2) Create a single tape Turing machine M_2 to decides the @lang of binary strings that contain at least 2 consecutive *{1}s !{or} an even number of \[1]s.
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