$($a$)$ Two capacitors of equal value C are connected to a ba$.$ery of poten$-$al

difference V volts. Circle appropriate answer for each of the condi$-$on below:

If Ctotal $=2$C then the charge on each capacitor is Q$/22$Q

If Ctotal $=$ C$/2,$ then the Pot Difference across each V$/22$V

$($b$)$ To use a Galvanometer as an ammeter connect a$\_\_\_\_\_\_\_\_\_\_\_\_$ resistance in $\_\_\_\_\_\_\_\_\_$

To use a Galvanometer as an Voltmeter Connect a $\_\_\_\_\_\_\_\_\_\_\_$resistance in$\_\_\_\_\_\_\_\_\_$

$($ Choose from Large, Small, Series and Parallel$)$

$($C$)$ A fully charged parallel plate capacitor remains connected to a ba$.$ery when you gently

slide a dielectric with dielectric constant K between the plates.

Which of the quan$--$es increase $($I$),$ decrease $($D$)$ or remain the same $($S$).$

C Q E $$V Energy stored

$($d$)$ The drift velocity vd for electrons for a $14$ gauge Cu wire carrying $1$A current

was calculated in class $($and posted on blackboard$)$ gave an answer of $3\mathrm{.}55$ x$10-3$

cm$/$s$.$ So for a $1000$ m long wire carrying current to an incandescent $($filament type$)$

bulb it may take up to $355$ seconds $($about $6$ min$).$ But you know the bulb lights up

instantaneously when the switch is turned ON$.$ Which of the reasons below is the

most appropriate?

A$.$ Light energy travels faster than the electrons in the wire

B$.$ Drift velocity vd may be small but energy is transferred from electron to

electron instantly

C$.$ The potential difference is set up all along the length of the wire instantly

D$.$ Drift velocity of electrons vd may be small, but current I, a scalar, travels at

the speed of light at $3$x$108$ m$/$s

E$.$ Electrons already present in the conductor are instantly affected by the E field

at $3$x$108$ m$/$s

F$.$ Cu wire is a conductor with very very small resistance so current travels to the

bulb instantly