A uniform bar has mass $0\mathrm{.}0180$ kgkg and is $30\mathrm{.}0$cmcm long. It pivots without friction about an axis perpendicular to the bar at point aa in $($Figure $1).$ The gravitational force on the bar acts in the $$y$$y$-$direction. The bar is in a uniform magnetic field that is directed into the page and has magnitude $0\mathrm{.}350$ BB $.$What must be the current II in the bar for the bar to be in rotational equilibrium when it is at an angle $40\mathrm{.}0$ above the horizontal? Use the fact that $=12$IBL$2$$=12$IBL$2$ for a uniform bar of length LL carring a current II in a magnetic field BB$.$

Express your answer with the appropriate units.