A vertical solid disk of uniform mass $M=5kg$ and radius $R=0,66m$ is pivoted from point $O$ as shown in the figure below. A constant force of $F=119N,$ making an angle of $=36$ with the tangent is applied. If $x=0,32m,$ determine the angular acceleration of the disk in $SI$ units at the instant shown. Express your answer using two decimal places. Please use the convention: Clockwise $(-),$ Counterclockwise $(+)$ when expressing your answer.

Hint $1$: The moment of inertia of a uniform disk about an axis of rotation passing through the center of mass $(CM)$ is $I_{CM}=M\frac{R^2}{2}.$

Hint $2$: Don't forget the force of gravity!!! Take $g=9\mathrm{.}80\frac{m}{s^2}.$

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