Question: A very thin 1 5 . 0 cmcm copper bar is aligned horizontally along the east - west direction. Part A If it moves horizontally

A very thin 15.0 cmcm copper bar is aligned horizontally along the east-west direction.
Part A
If it moves horizontally from south to north at 10.5 m/sm/s in a vertically upward magnetic field of 1.28 TT , what potential difference is induced across its ends?
Express your answer in volts.
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VabVab =
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VV
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Part B
If it moves horizontally from south to north at 10.5 m/sm/s in a vertically upward magnetic field of 1.28 TT , which end (east or west) is at a higher potential ?
eastwest
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Part C
What would be the potential difference if the bar moved from east to west instead?
Express your answer in volts.

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