A waterslide is built with bed slope Sb$=0\mathrm{.}003($dimensionless$)$ and width $1$m$.$ Its flowing at "normal flow" conditions with a smooth bed $($mannings roughness n$=0\mathrm{.}001)($dimensionless$).$ The flow is much wider than the depth, so you can approximate hydraulic radius Rh and depth d to be equal. Given depth d$=0\mathrm{.}02$m$,$ calculate the normal$-$flow discharge $($Q$).$