Question: a . We start by subdividing 3 , 1 1 into n equal width subintervals [ x 0 , x 1 ] , [ x

a. We start by subdividing 3,11 into n equal width subintervals [x0,x1],[x1,x2],dots,[xn-1,xn] each of width x. Express the width of each subinterval x in terms of the number of subintervals n.
x=
b. Find the right endpoints x1,x2,x3 of the first, second, and third subintervals x0,x1
x1,x2
x2,x3 and express your answers in terms of n.
x1,x2,x3=
Enter a comma separated list.)
c. Find a general expression for the right endpoint xk of the kth subinterval xk-1,xk, where 1kn. Express your answer in terms of k and n
xk=
d. Find f(xk) in terms of k and n.
f(xk)=(11+k8n)2
e. Find f(xk)x in terms of k and n.
f(xk)x=
f. Find the value of the right-endpoint Riemann sum in terms of n.
k=1nf(xk)x=
g. Find the limit of the right-endpoint Riemann sum.
limm(??nf(xk)x)=
a . We start by subdividing 3 , 1 1 into n equal

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