(a) What is the maximum number that we can count up to using 11 bits? [2...

    

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(a) What is the maximum number that we can count up to using 11 bits? [2 mark] (b) Given that Y = 13810 and X= 1728, using 8-bit 2'S complement signed binary arithmetic, perform X-Y. (c) Consider the following cases: [4 marks] (i) Convert 735s to decimal by multiplying its sum of weight. [2 marks] (ii) Simplify F = RS (T+RU) + STR using DeMorgan's theorem and/or Boolean Theorem. [5 marks] (iii) Convert ABE716 to Binary [2 marks] (a) What is the maximum number that we can count up to using 11 bits? [2 mark] (b) Given that Y = 13810 and X= 1728, using 8-bit 2'S complement signed binary arithmetic, perform X-Y. (c) Consider the following cases: [4 marks] (i) Convert 735s to decimal by multiplying its sum of weight. [2 marks] (ii) Simplify F = RS (T+RU) + STR using DeMorgan's theorem and/or Boolean Theorem. [5 marks] (iii) Convert ABE716 to Binary [2 marks]

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With 11 bits we can count up to a maximum number of 211 1 Calculating 211 1 2048 1 2047 Therefore we ... View the full answer