$($a$)$ What is wrong with the following equation? $\frac{x^2+x-6}{x-2}=x+3(x-2)(x+3)x^2+x-6$ The left$-$hand side is not defined for $x=0,$ but the right$-$hand side is$.$ The left$-$hand side is not defined for $x=2,$ but the right$-$hand side is$.$ None of these $-$ the equation is correct. $($b$)$ In view of part $($a$),$ explain why the following equation is correct. $\underset{x2}{lim}\frac{x^2+x-6}{x-2}=\underset{x2}{lim}(x+3)$ Since $\frac{x^2+x-6}{x-2}$ and $x+3$ are both continuous, the equation follows. Since the equation holds for all $x2,$ it follows that both sides of the equation approach the same limit as $x2.$ This equation