Question: A worker lowers a crate a distance 9.01 m down along a ramp. The ramp is inclined at an angle 5.73 degrees above horizontal. The


A worker lowers a crate a distance 9.01 m down along a ramp. The ramp is inclined at an angle 5.73 degrees above horizontal. The crate has a mass of 137 kg. The tension in the rope that is pulling the crate is 50.53 N, and the rope is parallel to the ramp. There is a 24.7 N kinetic friction force acting on the crate from the ramp's surface. How much work is done by the tension force the rope exerts on the crate during the trip? Work has units of energy---Jou|es in S.|. units. Remember that the work done by a force depends on the angle between the force vector and the displacement vector. Work can be positive or negative-"don't forget a if needed. W: J A 5.5-kg block is released from rest (v1 = 0) on a rough incline as in the figure below with 0 = 46. In 0.7 s, the block slides a distance d = 0.7 m down the incline, reaching a final speed of v2 = 3.4 m/s. Calculate the change in the block's gravitational potential energy during its slide. V1 m m 02 - APE = Record your answer below, assuming three significant figures. Remember to include a "-" if/when necessary
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