a) Write a template to help you solve this problem. Make sure your units are correct.

b) Write a script template accordingly as well

CA TA = -k - ) (x, Consider the following isothermal CSTR. The reaction occurring in the CSTR is k AB, Ks + CA The reactor is initially at steady state, with volumetric flow rate V (both inlet and outlet), constant reactor volume V, and feed concentration of A, CAF. There is no B in the feed. Therefore, the equations describing the concentration of A and B, over time, are: CA CA = D(Caf - CA) k dt K + CA dCB = -DCB + KCA (2) dt (where D is the dilution rate: D = V/V). Consider the situation in which the specified feed flow rate changes at time t = 0. This changes the dilution rate according to: dD 1 dt Ty 6,46) (1) (Dspec D) = In other words, Dspec is initially 0.1 min-1, and the reactor is operating at steady state, with CA 0.3583 mol/L. At time t = 0, D spec changes to 0.15 min-1. For this problem, include this equation for D now with the non-linear equation (1). You do not need to use equation (2). CA = 0.3583 mol/L n = 0.1 min-1 = CA = 0.3583 mol/L D = 0.1 min-1 mol CAF = 1" L mol Ks = 0.2 L mol k = 0.1 L min Ty = 2 s CA TA = -k - ) (x, Consider the following isothermal CSTR. The reaction occurring in the CSTR is k AB, Ks + CA The reactor is initially at steady state, with volumetric flow rate V (both inlet and outlet), constant reactor volume V, and feed concentration of A, CAF. There is no B in the feed. Therefore, the equations describing the concentration of A and B, over time, are: CA CA = D(Caf - CA) k dt K + CA dCB = -DCB + KCA (2) dt (where D is the dilution rate: D = V/V). Consider the situation in which the specified feed flow rate changes at time t = 0. This changes the dilution rate according to: dD 1 dt Ty 6,46) (1) (Dspec D) = In other words, Dspec is initially 0.1 min-1, and the reactor is operating at steady state, with CA 0.3583 mol/L. At time t = 0, D spec changes to 0.15 min-1. For this problem, include this equation for D now with the non-linear equation (1). You do not need to use equation (2). CA = 0.3583 mol/L n = 0.1 min-1 = CA = 0.3583 mol/L D = 0.1 min-1 mol CAF = 1" L mol Ks = 0.2 L mol k = 0.1 L min Ty = 2 s