$($a$)$ You short$-$circuit a $18$ volt battery by connecting a short wire from one end of the battery to the other end. If the current in the short circuit is measured to be $16$ amperes, what is the internal resistance of the battery?

$1\mathrm{.}125$

$1\mathrm{.}13$

$($b$)$ What is the power generated by the battery?

$288$

$288$

W

$($c$)$ How much energy is dissipated in the internal resistance every second? $($Remember that one watt is one joule per second.$)$

$288$

$288$

J

$($d$)$ This same battery is now connected to a $12$ resistor. How much current flows through this resistor?

$1\mathrm{.}371$

$1\mathrm{.}37$

A

$($e$)$ How much power is dissipated in the $12$ resistor?

$22\mathrm{.}569$

$22\mathrm{.}6$

W

$($f$)$ The leads to a voltmeter are placed at the two ends of the battery of this circuit containing the $12$ resistor. What does the meter read?

$16\mathrm{.}4576$

$16\mathrm{.}5$

V