A=4 B=5 C=6 D=2 E=7

a=0 b=1 c=0 d=0 e=1

5. For the below circuit shift Registers 1, 2 and 3 have initial values as given below (a, b, c ... are your numbers). Flip-flops A and B have initial states 0. Write the content of each register (1, 2, 3), flip-flop states A and B, flip-flop inputs DA and To, inputs to full adder x and y for 5 clock cycles in a tabular form. Everything works with the same clock inputs. (Note that it is not a serial adder or subtractor as B flip-flop is T, not D type). Register 1 Register 3 Full adder Sum a b c de X 0 0 0 0 0 y Register 2 Cout Cin a' b c do OD D -B T D