Question: ABC + B + ABD + AC ( b ) ABC + ABC + ABC + ABC + A'B'C' ( c ) A + B

ABC+B+ABD+AC
(b) ABC+ABC+ABC+ABC+A'B'C'
(c) A+B (AC+(B+C) D)
Simplify the given Boolean expressions to minimum numbers of terms and literals by applying laws and rules of Boolean algebra:
(a)AB'C+B+ABD'+A'C
(b) ABC+A'B'C+A'BC+ABC'+A'B'C'
(c)A+B[AC+(B+C')D]v
 ABC+B+ABD+AC (b) ABC+ABC+ABC+ABC+A'B'C' (c) A+B (AC+(B+C) D) Simplify the given Boolean

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